1.For the reaction, H2+I2⇌2HI\mathrm{H_2 + I_2 \rightleftharpoons 2HI}H2+I2⇌2HI, K = 47.6. If the initial number of moles of each reactant and product is 1 mole, then at equilibrium:a.[I2]=[H2]\mathrm{[I_2] = [H_2]}[I2]=[H2], [I2]>[HI]\mathrm{[I_2] > [HI]}[I2]>[HI]b.[I2]=[H2]\mathrm{[I_2] = [H_2]}[I2]=[H2], [I2]<[HI]\mathrm{[I_2] < [HI]}[I2]<[HI]c.[I2]<[H2]\mathrm{[I_2] < [H_2]}[I2]<[H2], [I2]=[HI]\mathrm{[I_2] = [HI]}[I2]=[HI]d.[I2]>[H2]\mathrm{[I_2] > [H_2]}[I2]>[H2], [I2]=[HI]\mathrm{[I_2] = [HI]}[I2]=[HI]Login to continueOnly logged in users canattempt or see the solution.
