1.Let f:R→Rf: \mathbb{R} \to \mathbb{R}f:R→R be defined asf(x)={x3(1−cos2x)2loge(1+2xe−2x(1−xe−x)2),x≠0α,x=0f(x) = \begin{cases} \frac{x^3}{(1 - \cos 2x)^2} \log_e\left(\frac{1 + 2x e^{-2x}}{(1 - x e^{-x})^2}\right), & x \neq 0 \\ \alpha, & x = 0 \end{cases}f(x)={(1−cos2x)2x3loge((1−xe−x)21+2xe−2x),α,x=0x=0If fff is continuous at x=0x = 0x=0, then α\alphaα is equal to:Login to continueOnly logged in users canattempt or see the solution.
