1.If α\alphaα and β\betaβ are roots of the equation x2−42kx+2e4lnk−1=0x^2 - 4\sqrt{2}kx + 2e^{4\ln k} - 1 = 0x2−42kx+2e4lnk−1=0 for some kkk, and α2+β2=66\alpha^2 + \beta^2 = 66α2+β2=66, then α3+β3\alpha^3 + \beta^3α3+β3 is equal toa.2482248\sqrt{2}2482b.2802280\sqrt{2}2802c.−322-32\sqrt{2}−322d.−2802-280\sqrt{2}−2802Login to continueOnly logged in users canattempt or see the solution.
