1.If the dimensions of a physical quantity are given by [MaLbTc][M^a L^b T^c][MaLbTc], then the physical quantity will be:a.Force if a=0a = 0a=0, b=−1b = -1b=−1, c=−2c = -2c=−2b.Pressure if a=1a = 1a=1, b=−1b = -1b=−1, c=−2c = -2c=−2c.Velocity if a=1a = 1a=1, b=0b = 0b=0, c=−1c = -1c=−1d.Acceleration if a=1a = 1a=1, b=1b = 1b=1, c=−2c = -2c=−2Login to continueOnly logged in users canattempt or see the solution.
