1.Three numbers are chosen at random without replacement from {1,2,3,…,8}\{1, 2, 3, \ldots, 8\}{1,2,3,…,8}. The probability that their minimum is 3, given that their maximum is 6, is :a.25\frac{2}{5}52b.38\frac{3}{8}83c.15\frac{1}{5}51d.14\frac{1}{4}41Login to continueOnly logged in users canattempt or see the solution.
