1.General solution of the differential equation ey dx+(xey−2y) dy=0e^y\,dx + (xe^y - 2y)\,dy = 0eydx+(xey−2y)dy=0 isa.xey−y2=cxe^y - y^2 = cxey−y2=cb.yex−x2=cye^x - x^2 = cyex−x2=cc.yey+x=cye^y + x = cyey+x=cd.xey−1=cy2xe^y - 1 = cy^2xey−1=cy2Login to continueOnly logged in users canattempt or see the solution.
