1.Two functions f:R→Rf : \mathbb{R} \to \mathbb{R}f:R→R, g:R→Rg : \mathbb{R} \to \mathbb{R}g:R→R are defined as follows f(x)={0,x is rational1,x is irrationalf(x) = \begin{cases} 0, & x \text{ is rational} \\ 1, & x \text{ is irrational} \end{cases}f(x)={0,1,x is rationalx is irrational, g(x)={−1,x is rational0,x is irrationalg(x) = \begin{cases} -1, & x \text{ is rational} \\ 0, & x \text{ is irrational} \end{cases}g(x)={−1,0,x is rationalx is irrational. Then, (f∘g)(π)+(g∘f)(e)(f \circ g)(\pi) + (g \circ f)(e)(f∘g)(π)+(g∘f)(e) is equal toa.000b.−1-1−1c.222d.111Login to continueOnly logged in users canattempt or see the solution.
