1.Two intervals of time are measured as Δt1=(2.00±0.02) s\Delta t_1 = (2.00 \pm 0.02)\,\text{s}Δt1=(2.00±0.02)s and Δt2=(4.00±0.02) s\Delta t_2 = (4.00 \pm 0.02)\,\text{s}Δt2=(4.00±0.02)s. The value of Δt1Δt2\sqrt{\Delta t_1 \Delta t_2}Δt1Δt2 with correct significant figures and error isa.(2.828±0.01) s(2.828 \pm 0.01)\,\text{s}(2.828±0.01)sb.(2.83±0.01) s(2.83 \pm 0.01)\,\text{s}(2.83±0.01)sc.(2.828±0.0075) s(2.828 \pm 0.0075)\,\text{s}(2.828±0.0075)sd.(2.83±0.0075) s(2.83 \pm 0.0075)\,\text{s}(2.83±0.0075)sLogin to continueOnly logged in users canattempt or see the solution.
