1.A particle is executing SHM of amplitude AAA and angular frequency ω\omegaω. The average acceleration of the particle for half the time period (starting from the mean position) isa.2Aω2π\dfrac{2A\omega^2}{\pi}π2Aω2b.Aω2π\dfrac{A\omega^2}{\pi}πAω2c.3Aω22π\dfrac{3A\omega^2}{2\pi}2π3Aω2d.Aω22\dfrac{A\omega^2}{2}2Aω2Login to continueOnly logged in users canattempt or see the solution.