1.\frac{d}{dx} \sin^{-1} (3x - 4x^3) is equal toa.\frac{3}{\sqrt{4-x^2}}b.\frac{3}{\sqrt{1-x^2}}c.\frac{1}{\sqrt{4-x^2}}d.-\frac{1}{\sqrt{4-x^2}}Login to continueOnly logged in users canattempt or see the solution.
