1.In a meeting 60% of the members favour and 40% oppose a certain proposal. A member is selected at random and we take X=0X=0X=0 if the opposed and X=1X=1X=1 if he is in favour, then Var(X)=(X) =(X)=a.0.36b.0.24c.0.6d.0.06Login to continueOnly logged in users canattempt or see the solution.