1.Let fff and ggg be two functions defined byf(x)={x+1,x<0∣x−1∣,x>0f(x) = \begin{cases} x+1, & x < 0 \\ |x-1|, & x > 0 \end{cases}f(x)={x+1,∣x−1∣,x<0x>0andg(x)={x+1,x<01,x≥0g(x) = \begin{cases} x+1, & x < 0 \\ 1, & x \geq 0 \end{cases}g(x)={x+1,1,x<0x≥0Then (g∘f)(x)(g \circ f)(x)(g∘f)(x) isLogin to continueOnly logged in users canattempt or see the solution.