1.If aaa and bbb are positive integers such that N=(a+ib)3−107iN = (a + ib)^3 - 107iN=(a+ib)3−107i (where NNN is a natural number), then the value of aaa is equal to (where i2=−1i^2 = -1i2=−1)a.444b.555c.666d.999Login to continueOnly logged in users canattempt or see the solution.