1.A steel wire of length LLL has a magnetic moment MMM. It is then bent into a semi-circular arc; the new magnetic moment will be:a.MMMb.2Mπ\dfrac{2M}{\pi}π2Mc.ML\dfrac{M}{L}LMd.M×LM \times LM×LLogin to continueOnly logged in users canattempt or see the solution.
