1.If the locus of z∈Cz \in \mathbb{C}z∈C such that arg(z−1z+1)=π2\arg\left(\dfrac{z - 1}{z + 1}\right) = \dfrac{\pi}{2}arg(z+1z−1)=2π is a circle of radius rrr and centre (a,b)(a, b)(a,b), then 15ab15ab15ab is equal to:a.242424b.121212c.181818d.161616Login to continueOnly logged in users canattempt or see the solution.
