1.The enthalpy change (ΔH\Delta HΔH) for the reaction N2(g)+3H2(g)→2NH3(g)N_{2(g)} + 3H_{2(g)} \rightarrow 2NH_{3(g)}N2(g)+3H2(g)→2NH3(g) is −92.38-92.38−92.38 kJ at 298 K. The internal energy change ΔU\Delta UΔU at 298 K isa.−92.38-92.38−92.38 kJb.−87.42-87.42−87.42 kJc.−97.34-97.34−97.34 kJd.−89.9-89.9−89.9 kJLogin to continueOnly logged in users canattempt or see the solution.
