1.A 0.1 molal solution of an acid is 4.5% ionized. Calculate freezing point. (Molecular weight of the acid is 300). Kf=1.86K_f = 1.86Kf=1.86 K mol−1^{-1}−1 kg.a.0.194∘0.194^\circ0.194∘Cb.2.00∘2.00^\circ2.00∘Cc.0∘0^\circ0∘Cd.−0.269∘-0.269^\circ−0.269∘CLogin to continueOnly logged in users canattempt or see the solution.
