1.The Boolean expression ((p∧q)∨(p∨¬q))∧(¬p∧¬q)((p \land q) \lor (p \lor \neg q)) \land (\neg p \land \neg q)((p∧q)∨(p∨¬q))∧(¬p∧¬q) is equivalent toa.p∧(¬q)p \land (\neg q)p∧(¬q)b.(¬p)∧(¬q)(\neg p) \land (\neg q)(¬p)∧(¬q)c.p∨(¬q)p \lor (\neg q)p∨(¬q)d.p∧qp \land qp∧qLogin to continueOnly logged in users canattempt or see the solution.
