1.For the system of linear equationsx+y+z=6x + y + z = 6x+y+z=6αx+βy+7z=3\alpha x + \beta y + 7z = 3αx+βy+7z=3x+2y+3z=14x + 2y + 3z = 14x+2y+3z=14which of the following is NOT true?a.If α=β=7\alpha = \beta = 7α=β=7, then the system has no solutionb.If α=β\alpha = \betaα=β and α≠7\alpha \neq 7α=7 then the system has a unique solutionc.There is a unique point (α,β)(\alpha, \beta)(α,β) on the line x+2y+18=0x + 2y + 18 = 0x+2y+18=0 for which the system has infinitely many solutionsd.For every point (α,β)≠(7,7)(\alpha, \beta) \neq (7, 7)(α,β)=(7,7) on the line x−2y+7=0x - 2y + 7 = 0x−2y+7=0, the system has infinitely many solutionsLogin to continueOnly logged in users canattempt or see the solution.