1.Hydrocarbon A on reductive ozonolysis gives two isomeric forms B and C. B on oxidation using Tollens reagent gives D. Identify the structure of hydrocarbon A.a.2-Methyl-2-butene (CH3−CH=C(CH3)2\mathrm{CH_3{-}CH=C(CH_3)_2}CH3−CH=C(CH3)2)b.2-Methyl-2-pentene (CH3−CH2−CH2−C(CH3)=CH−CH3\mathrm{CH_3{-}CH_2{-}CH_2{-}C(CH_3)=CH{-}CH_3}CH3−CH2−CH2−C(CH3)=CH−CH3)c.3-Methyl-3-octene (CH3−CH2−CH2−CH2−C(CH3)=CH−CH2−CH2−CH3\mathrm{CH_3{-}CH_2{-}CH_2{-}CH_2{-}C(CH_3)=CH{-}CH_2{-}CH_2{-}CH_3}CH3−CH2−CH2−CH2−C(CH3)=CH−CH2−CH2−CH3)d.4-Methyl-3-heptene (CH3−CH=CH−C(CH3)(CH2CH2CH3)\mathrm{CH_3{-}CH=CH{-}C(CH_3)(CH_2CH_2CH_3)}CH3−CH=CH−C(CH3)(CH2CH2CH3))Login to continueOnly logged in users canattempt or see the solution.