1.f(x)={[tan(1+x)]1/2x,x≠0K,x=0f(x)=\begin{cases}[\tan(1+x)]^{1/2x},&x\ne0\\K,&x=0\end{cases}f(x)={[tan(1+x)]1/2x,K,x=0x=0 cont at 000, k=k=k=a.eeeb.e−1e^{-1}e−1c.e2e^2e2d.e−2e^{-2}e−2Login to continueOnly logged in users canattempt or see the solution.
