1.Let a,b∈Ra, b \in \mathbb{R}a,b∈R, a≠0a \neq 0a=0 be such that the equation ax2−2bx+5=0ax^2 - 2bx + 5 = 0ax2−2bx+5=0 has a repeated root α\alphaα, which is also a root of the equation x2−2bx−10=0x^2 - 2bx - 10 = 0x2−2bx−10=0. If β\betaβ is the other root of this equation, then α2+β2\alpha^2 + \beta^2α2+β2 is equal to:a.252525b.262626c.282828d.242424Login to continueOnly logged in users canattempt or see the solution.