1.
An object is projected with a velocity of 20m/s20\,\text{m/s} making an angle of 4545^\circ with horizontal. The equation for the trajectory is h=AxBx2h = Ax - Bx^2 where hh is height, xx is horizontal distance, AA and BB are constants. The ratio A:BA : B is (g=10m/s2)(g = 10\,\text{m/s}^2)