1.The displacement yyy of a particle in a medium can be expressed as y=10−6sin(100t+20x+π/4)y = 10^{-6}\sin(100t + 20x + \pi/4)y=10−6sin(100t+20x+π/4) m where ttt is in second and xxx in meter. The speed of the wave isa.20 m/sb.5 m/sc.2000 m/sd.5π5\pi5π m/sLogin to continueOnly logged in users canattempt or see the solution.