1.Let α,β,γ\alpha, \beta, \gammaα,β,γ be the three roots of the equation x3+bx+c=0x^3 + bx + c = 0x3+bx+c=0. If βγ=1=−α\beta\gamma = 1 = -\alphaβγ=1=−α, then b3+2c3−3α3−6β3−8γ3b^3 + 2c^3 - 3\alpha^3 - 6\beta^3 - 8\gamma^3b3+2c3−3α3−6β3−8γ3 is equal toa.155155155b.212121c.169169169d.191919Login to continueOnly logged in users canattempt or see the solution.
