1.If 1−x+6x21−x3=Ax+B1+x+C1+x\frac{1-x+6x^2}{1-x^3} = \frac{A}{x} + \frac{B}{1+x} + \frac{C}{1+x}1−x31−x+6x2=xA+1+xB+1+xC, then AAA is equal toa.111b.222c.333d.444Login to continueOnly logged in users canattempt or see the solution.
