1.The set of values of xxx such that tan−1(xx−2)−tan−1(x2x−1)=tan−1(23)\tan^{-1} \left(\frac{x}{x-2}\right) - \tan^{-1} \left(\frac{x}{2x-1}\right) = \tan^{-1} \left(\frac{2}{3}\right)tan−1(x−2x)−tan−1(2x−1x)=tan−1(32) isa.ϕ\phiϕb.{12}\{\frac{1}{2}\}{21}c.{13,2}\{\frac{1}{3}, 2\}{31,2}d.{13,4}\{\frac{1}{3}, 4\}{31,4}Login to continueOnly logged in users canattempt or see the solution.
