1.If the system of equationsx+2y+3z=34x+3y−4z=48x+4y−λz=9+μ\begin{aligned} x + 2y + 3z &= 3 \\ 4x + 3y - 4z &= 4 \\ 8x + 4y - \lambda z &= 9 + \mu \end{aligned}x+2y+3z4x+3y−4z8x+4y−λz=3=4=9+μhas infinitely many solutions, then the ordered pair (λ,μ)(\lambda, \mu)(λ,μ) is equal to:a.(7,1)(7, 1)(7,1)b.(−7,−1)(-7, -1)(−7,−1)c.(72,12)\left(\dfrac{7}{2}, \dfrac{1}{2}\right)(27,21)d.(−72,−12)\left(-\dfrac{7}{2}, -\dfrac{1}{2}\right)(−27,−21)Login to continueOnly logged in users canattempt or see the solution.