1.If A=[3201]A = \begin{bmatrix}3&2\\0&1\end{bmatrix}A=[3021], then (A−1)3=(A^{-1})^3 =(A−1)3=a.127[1−26027]\frac{1}{27}\begin{bmatrix}1&-26\\0&27\end{bmatrix}271[10−2627]b.127[−1−26027]\frac{1}{27}\begin{bmatrix}-1&-26\\0&27\end{bmatrix}271[−10−2627]c.127[1−260−27]\frac{1}{27}\begin{bmatrix}1&-26\\0&-27\end{bmatrix}271[10−26−27]d.127[−1−260−27]\frac{1}{27}\begin{bmatrix}-1&-26\\0&-27\end{bmatrix}271[−10−26−27]Login to continueOnly logged in users canattempt or see the solution.
