1.If x+y=3cos4θx+y = 3\cos 4\thetax+y=3cos4θ and x−y=4sin2θx-y = 4\sin 2\thetax−y=4sin2θ, thena.x2+y2=9x^2+y^2 = 9x2+y2=9b.x+y=16\sqrt{x}+\sqrt{y} = 16x+y=16c.x3+y3=2(x2+y2)x^3+y^3 = 2(x^2+y^2)x3+y3=2(x2+y2)d.x+y=2\sqrt{x}+\sqrt{y} = 2x+y=2Login to continueOnly logged in users canattempt or see the solution.
