1.If aaa, bbb and ccc are the greatest values of 19Cp^{19}C_{p}19Cp, 20Cq^{20}C_{q}20Cq and 21Cr^{21}C_{r}21Cr respectively, then:a.a11=b22=c42\dfrac{a}{11} = \dfrac{b}{22} = \dfrac{c}{42}11a=22b=42cb.a10=b11=c42\dfrac{a}{10} = \dfrac{b}{11} = \dfrac{c}{42}10a=11b=42cc.a11=b22=c42\dfrac{a}{11} = \dfrac{b}{22} = \dfrac{c}{42}11a=22b=42cd.a10=b20=c42\dfrac{a}{10} = \dfrac{b}{20} = \dfrac{c}{42}10a=20b=42cLogin to continueOnly logged in users canattempt or see the solution.
