1.If f(x)={sin−1x+acosx,−1<x<0bcos−1x+sinπx,0≤x≤1f(x)=\begin{cases} \sin^{-1}x + a\cos x, & -1<x<0 \\ b\cos^{-1}x + \sin\pi x, & 0\leq x\leq 1 \end{cases}f(x)={sin−1x+acosx,bcos−1x+sinπx,−1<x<00≤x≤1 is differentiable in (−1,1)(-1,1)(−1,1), then (2a+b)(2a+b)(2a+b) is equal toa.π2\pi^2π2b.1+π21+\pi^21+π2c.1−π21-\pi^21−π2d.π2−1\pi^2-1π2−1Login to continueOnly logged in users canattempt or see the solution.
