1.If ∑i=1n(xi−a)=n\sum_{i=1}^{n}(x_i - a) = n∑i=1n(xi−a)=n and ∑i=1n(xi−a)2=na\sum_{i=1}^{n}(x_i - a)^2 = na∑i=1n(xi−a)2=na, with n,a>1n, a > 1n,a>1, then the standard deviation of the nnn observations x1,x2,…,xnx_1, x_2, \ldots, x_nx1,x2,…,xn is:a.a−1a - 1a−1b.n(a−1)\sqrt{n(a-1)}n(a−1)c.n (a−1)\sqrt{n}\,(a-1)n(a−1)d.a−1\sqrt{a-1}a−1Login to continueOnly logged in users canattempt or see the solution.
