1.For the system of linear equations2x+4y+2αz=bx+2y+3z=42x+5y+2z=8\begin{aligned} 2x + 4y + 2\alpha z &= b \\ x + 2y + 3z &= 4 \\ 2x + 5y + 2z &= 8 \end{aligned}2x+4y+2αzx+2y+3z2x+5y+2z=b=4=8which of the following is NOT correct?a.It has a unique solution if α=b=6\alpha = b = 6α=b=6b.It has infinitely many solutions if α=3\alpha = 3α=3, b=6b = 6b=6c.It has infinitely many solutions if α=3\alpha = 3α=3, b=8b = 8b=8d.It has a unique solution if α=b=8\alpha = b = 8α=b=8Login to continueOnly logged in users canattempt or see the solution.
