1.If x=1−t21+t2x = \frac{1-t^2}{1+t^2}x=1+t21−t2 and y=2t1+t2y = \frac{2t}{1+t^2}y=1+t22t, then dydx\frac{dy}{dx}dxdy is equal to :a.−yx-\frac{y}{x}−xyb.yx\frac{y}{x}xyc.−xy-\frac{x}{y}−yxd.xy\frac{x}{y}yxLogin to continueOnly logged in users canattempt or see the solution.
