1.f(x)={xpsin(1/x),x≠00,x=0f(x)=\begin{cases}x^p\sin(1/x),&x\ne0\\0,&x=0\end{cases}f(x)={xpsin(1/x),0,x=0x=0 cont but not diff ifa.p<0p<0p<0b.p=0p=0p=0c.0<p≤10<p\le10<p≤1d.p≥1p\ge1p≥1Login to continueOnly logged in users canattempt or see the solution.
