1.(dydx)tanx=ysec2x+sinx(\frac{dy}{dx})\tan x = y\sec^2 x + \sin x(dxdy)tanx=ysec2x+sinx, find general solutiona.y=tanx(log∣cscx−cotx∣+cosx+c)y = \tan x(\log|\csc x - \cot x| + \cos x + c)y=tanx(log∣cscx−cotx∣+cosx+c)b.y=sec2x+tanx+cy = \sec^2 x + \tan x + cy=sec2x+tanx+cc.y=log∣secx+tanx∣+cscx+cy = \log|\sec x + \tan x| + \csc x + cy=log∣secx+tanx∣+cscx+cd.y=tan2x+sinx+cy = \tan^2 x + \sin x + cy=tan2x+sinx+cLogin to continueOnly logged in users canattempt or see the solution.
