1.Tangent to 4y2=x2+14y^2=x^2+14y2=x2+1 meets axes at A,BA,BA,B. Locus of midpoint of ABABAB isa.x2−4y2+16x2y2=0x^2-4y^2+16x^2y^2=0x2−4y2+16x2y2=0b.4x2−y2+16x2y2=04x^2-y^2+16x^2y^2=04x2−y2+16x2y2=0c.x2−4y2−16x2y2=0x^2-4y^2-16x^2y^2=0x2−4y2−16x2y2=0d.4x2−y2−16x2y2=04x^2-y^2-16x^2y^2=04x2−y2−16x2y2=0Login to continueOnly logged in users canattempt or see the solution.
