1.Two particles A and B of same mass have their de-Broglie wavelengths in the ratio λA:λB=K:1\lambda_A : \lambda_B = K : 1λA:λB=K:1. Their potential energies UA:UB=1:K2U_A : U_B = 1 : K^2UA:UB=1:K2. The ratio of their total energies EA:EBE_A : E_BEA:EB isa.K2:1K^2 : 1K2:1b.1:K21 : K^21:K2c.K:1K : 1K:1d.1:K1 : K1:KLogin to continueOnly logged in users canattempt or see the solution.