1.If D, E and F are respectively the mid-points of AB, AC and BC in △ABC\triangle ABC△ABC, then BE→+AF→\overrightarrow{BE} + \overrightarrow{AF}BE+AF is equal toa.DC→\overrightarrow{DC}DCb.12BF→\frac{1}{2} \overrightarrow{BF}21BFc.2BF→2 \overrightarrow{BF}2BFd.32BF→\frac{3}{2} \overrightarrow{BF}23BFLogin to continueOnly logged in users canattempt or see the solution.
