1.Let A=(aij)2×2=(log5128log58log425log45)A = \begin{pmatrix} a_{ij} \end{pmatrix}_{2 \times 2} = \begin{pmatrix} \log_{5} 128 & \log_{5} 8 \\ \log_{4} 25 & \log_{4} 5 \end{pmatrix}A=(aij)2×2=(log5128log425log58log45). If AijA_{ij}Aij is the cofactor of aija_{ij}aij, Cij=∑kaikAjk, 1≤i,j≤2C_{ij} = \sum_{k} a_{ik} A_{jk}, \; 1 \le i, j \le 2Cij=∑kaikAjk,1≤i,j≤2, and C=[Cij]C = [C_{ij}]C=[Cij], then 8∣C∣8|C|8∣C∣ is equal to:a.288288288b.222222222c.242242242d.262262262Login to continueOnly logged in users canattempt or see the solution.