1.If 10%10\%10% of the power of a (100π)(100\pi)(100π) W light bulb is converted to visible radiation, then the average intensity of visible radiation at a distance of 101010 m isa.0.0250.0250.025 W m−2^{-2}−2b.0.010.010.01 W m−2^{-2}−2c.0.0310.0310.031 W m−2^{-2}−2d.0.050.050.05 W m−2^{-2}−2Login to continueOnly logged in users canattempt or see the solution.