1.
If the truth value of the Boolean expression

((p∨q)∧(q⇒r)∧(∼r))⇒(p∧q)((p \vee q) \wedge (q \Rightarrow r) \wedge (\sim r)) \Rightarrow (p \wedge q)

is false, then the truth values of the statements p,q,rp, q, r respectively can be: