1.If secA+tanA=p\sec A + \tan A = psecA+tanA=p, then what is the value of sinA\sin AsinA?a.p2−1p2+1\frac{p^2 - 1}{p^2 + 1}p2+1p2−1b.p2+1p2−1\frac{p^2 + 1}{p^2 - 1}p2−1p2+1c.1d.None of theseLogin to continueOnly logged in users canattempt or see the solution.
