1.Let α\alphaα and β\betaβ be real numbers. Consider a 3×33 \times 33×3 matrix AAA such that A2=3A+αIA^{2} = 3A + \alpha IA2=3A+αI. If A4=21A+βIA^{4} = 21A + \beta IA4=21A+βI, then:a.α=1\alpha = 1α=1b.α=4\alpha = 4α=4c.β=8\beta = 8β=8d.β=−8\beta = -8β=−8Login to continueOnly logged in users canattempt or see the solution.
