1.If A=[1234]A = \begin{bmatrix} 1 & 2 \\ 3 & 4 \end{bmatrix}A=[1324], then A−1=A^{-1} =A−1=a.12[4−2−31]\frac{1}{2} \begin{bmatrix} 4 & -2 \\ -3 & 1 \end{bmatrix}21[4−3−21]b.12[4−2−31]\frac{1}{2} \begin{bmatrix} 4 & -2 \\ -3 & 1 \end{bmatrix}21[4−3−21]c.[−2413]\begin{bmatrix} -2 & 4 \\ 1 & 3 \end{bmatrix}[−2143]d.[2413]\begin{bmatrix} 2 & 4 \\ 1 & 3 \end{bmatrix}[2143]Login to continueOnly logged in users canattempt or see the solution.
