1.Three particles, each with charge 10 μ10\,\mu10μC, are at corners of an equilateral triangle of side 101010 cm. The electrostatic potential energy of the system is (14πε0=9×109(\frac{1}{4\pi\varepsilon_0} = 9\times10^9(4πε01=9×109 Nm2^22/C2^22)a.Zerob.∞\infty∞c.272727 Jd.100100100 JLogin to continueOnly logged in users canattempt or see the solution.