1.
The chemical reaction 2O3→3O22O_3 \to 3O_2 proceeds as follows:
O3→(Fast)O2+OO_3 \xrightarrow{\text{(Fast)}} O_2 + O
O+O3→(Slow)2O2O + O_3 \xrightarrow{\text{(Slow)}} 2O_2

The rate law expression should be: