1.The number of real roots of the equation,e4x+e3x−4e2x+ex+1=0e^{4x} + e^{3x} - 4e^{2x} + e^x + 1 = 0e4x+e3x−4e2x+ex+1=0is:a.111b.333c.222d.444Login to continueOnly logged in users canattempt or see the solution.
