1.In a photoemissive cell with exciting wavelength λ\lambdaλ, the fastest electron has speed vvv. If the exciting wavelength is changed to 3λ/43\lambda/43λ/4, the speed of the fastest emitted electron will bea.v(3/4)1/2v(3/4)^{1/2}v(3/4)1/2b.v(4/3)1/2v(4/3)^{1/2}v(4/3)1/2c.Less than v(4/3)1/2v(4/3)^{1/2}v(4/3)1/2d.Greater than v(4/3)1/2v(4/3)^{1/2}v(4/3)1/2Login to continueOnly logged in users canattempt or see the solution.